Solution
\begin{aligned}
&\sum M_{A}=0 \\
&6 P \cdot 2-V_{C} \cdot 4-3 P \cdot 7=0 \\
&V_{C}=-\frac{9}{4} P \\
&\sum M_{C}=0 \\
&V_{A} \cdot 4-6 P \cdot 2-3 P \cdot 3=0 \\
&V_{A}=\frac{21}{4} P
\end{aligned}
\begin{aligned}
&A=18 \cdot 2+20 \cdot 1.2+181.6=103.2 \mathrm{~cm}^{2} \\
&\frac{A}{2}=51.6 \mathrm{~cm}^{2} \\
&\frac{A}{2}=18 \cdot 1.6+1.2 x=51.6 \\
&x=19 \\
&S_{y p l 1}=18 \cdot 2.8 \cdot(1+1.4)+1 \cdot 1.2 \cdot 12=121.56 \mathrm{~cm}^{3} \\
&S_{y p l 2}=18 \cdot 1.6 \cdot(19+0.8)+19 \cdot 1.2 \cdot \frac{19}{2}=786.84 \mathrm{~cm}^{3} \\
&W_{p l}=908.4 \mathrm{~cm}^{3} \\
&\left|\frac{M}{W}\right| \leq \operatorname{sigmaP} \\
&10.5 P \leq 908.4 \cdot 10^{-6} \cdot 195 \cdot 10^{6} \\
&P \leq 16.87 \mathrm{kN}
\end{aligned}
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